2x^2+33x-30=0

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Solution for 2x^2+33x-30=0 equation:



2x^2+33x-30=0
a = 2; b = 33; c = -30;
Δ = b2-4ac
Δ = 332-4·2·(-30)
Δ = 1329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{1329}}{2*2}=\frac{-33-\sqrt{1329}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{1329}}{2*2}=\frac{-33+\sqrt{1329}}{4} $

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